-[2z-(5z+1)]=1+(2z+2)

Solution for -[2z-(5z+1)]=1+(2z+2) equation:

Simplifying
-1[2z + -1(5z + 1)] = 1 + (2z + 2)

Reorder the terms:
-1[2z + -1(1 + 5z)] = 1 + (2z + 2)
-1[2z + (1 * -1 + 5z * -1)] = 1 + (2z + 2)
-1[2z + (-1 + -5z)] = 1 + (2z + 2)

Reorder the terms:
-1[-1 + 2z + -5z] = 1 + (2z + 2)

Combine like terms: 2z + -5z = -3z
-1[-1 + -3z] = 1 + (2z + 2)
[-1 * -1 + -3z * -1] = 1 + (2z + 2)
[1 + 3z] = 1 + (2z + 2)

Reorder the terms:
1 + 3z = 1 + (2 + 2z)

Remove parenthesis around (2 + 2z)
1 + 3z = 1 + 2 + 2z

Combine like terms: 1 + 2 = 3
1 + 3z = 3 + 2z

Solving
1 + 3z = 3 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
1 + 3z + -2z = 3 + 2z + -2z

Combine like terms: 3z + -2z = 1z
1 + 1z = 3 + 2z + -2z

Combine like terms: 2z + -2z = 0
1 + 1z = 3 + 0
1 + 1z = 3

Add '-1' to each side of the equation.
1 + -1 + 1z = 3 + -1

Combine like terms: 1 + -1 = 0
0 + 1z = 3 + -1
1z = 3 + -1

Combine like terms: 3 + -1 = 2
1z = 2

Divide each side by '1'.
z = 2

Simplifying
z = 2